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Joe placed six lettered counters on a 3-by-2 grid as shown, reading ENIGMA anticlockwise, and then he removed the E. Penny then slid the counters around, successively moving them up, down or across into a gap, so that after Joe replaced the E in its original position, the letters read ENIGMA clockwise.
What was the smallest number of counters that Penny needed to move to achieve this?
WIN 拢15 will be awarded to the sender of the first correct answer opened on Wednesday 17 February. The Editor鈥檚 decision is final. Please send entries to Enigma 1578, New 杏吧原创, Lacon House, 84 Theobald鈥檚 Road, London WC1X 8NS, or to enigma@newscientist.com (please include your postal address).
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Answer to 1572 Just magic: 66 is in its correct position
The winner Rick Eggleston of Surrey Hills, Victoria, Australia